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CDCS考試內容 - CDCS熱門考題

EXIN CDCS 認證考試是個檢驗IT專業知識的認證考試。VCESoft是個能幫你快速通過EXIN CDCS 認證考試的網站。在您考試之前使用我們提供的針對性培訓和測試練習題和答案，短時間內你會有很大的收穫。

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雖然大多數人會覺得通過EXIN CDCS認證考試很難。但是如果你選擇了我們的VCESoft，你會覺得拿到EXIN CDCS認證考試的證書不是那麼難了。VCESoft的訓練工具很全面，包含線上服務和售後服務。我們的線上服務是研究資料，它包含類比訓練題，和EXIN CDCS認證考試相關的考試練習題和答案。售後服務是VCESoft不僅能提供最新的EXIN CDCS認證考試練習題和答案以及動態消息，還不斷的更新考試練習題和答案和裝訂。

EXIN CDCS 考試大綱：

主題
簡介

主題 1

• Data Centre Environmental Considerations and Efficiency: This section evaluates the proficiency of data center professionals in addressing environmental factors and promoting efficiency within data center operations. The target audience, including data center managers and engineers, will be tested on their ability to identify and implement measures that enhance energy efficiency, cooling management, and sustainable practices.

主題 2

• Designing and Implementing a Data Centre: In this module, the exam assesses the knowledge of Exin data center professionals tasked with the design and implementation of data centers. Candidates will learn the key principles of creating an efficient data center layout, including considerations for scalability, redundancy, and security.

主題 3

• Data Centre Life Cycle and Standards: This section of the exam measures the skills of data center professionals and covers the various stages involved in the life cycle of a data center, from planning and design to implementation and decommissioning.

最新的 EPI Data Centre CDCS 免費考試真題 (Q34-Q39):

問題 #34
You are allowed to use a calculator for this question.
A computer room has a net volume of approximately 2,500 m³ / 88,287 ft³.
The temperature is 20 °C / 68 °F.
The required design concentration is 7%.
The S-Factor is 0.1359 (metric) / 1.885 (imperial).
Calculate the amount of gas required for this computer room based on FM200. What is the correct weight?

• A. Approximately 1,640 kg / 3,600 lbs
• B. Approximately 820 kg / 1,800 lbs
• C. Approximately 410 kg / 900 lbs
• D. Approximately 1,390 kg / 3,000 lbs

答案：B

解題說明：
The amount of FM200 gas required can be calculated using the formula:
Weight of Gas=Net Volume×Design Concentration×S-Factor ext{Weight of Gas} = ext{Net Volume} imes ext{Design Concentration} imes ext{S-Factor}Weight of Gas=Net Volume×Design Concentration×S-Factor Using metric units:
Net Volume: 2,500 m³
Design Concentration: 7% (or 0.07)
S-Factor: 0.1359
Calculation:
2,500 m3×0.07×0.1359=821.325 kg2,500 , ext{m}